Quote:
Originally Posted by fool
The chances were always 50/50 because by design the host will eliminate an empty curtain, so by design there's only two curtains, one of which has the car.
The stuff about the host and the curtain has no more impact on the odds than the host putting on his hairpiece or not, it's just part of the show leading up to a choice between two curtains.
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Seems like it, but no.
Here's a very simple way to test it for yourself with a deck of cards (you can do it with three cards, more closely simulating the game, but it takes a lot longer to see the pattern, while this ought to take about 20 seconds):
Curtains = Cards
Winning curtain (car) = Ace of Spades
Losing curtains (not car) = Non-Ace of Spades cards
- Pick a card from a full, shuffled deck. You want the Ace of Spades.
- Look at the card. If you didn't choose the Ace of Spades, you should have switched.
Here's what's going on:
- You choose a random curtain (you choose a random card)
- The host knowingly shows you an empty curtain, leaving one (someone shows you 50 non-AoS cards, leaving one card)
- You're offered a chance to switch curtains (you're offered to switch your card for the one remaining card)
You can obviously do it with someone else, and actually have them look through the deck and show you/discard 50 non-AoS cards, but all you really need to do is pick a card and see if it's the AoS. If it's not, then you should have switched.
Quote:
Originally Posted by fool
by design the host will eliminate an empty curtain
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I'll point out that it's
precisely because of this design that it helps you. The host has to knowingly be opening an empty curtain for you. Otherwise, is it's 50/50 and it doesn't matter if you switch.
The host must know what's behind the curtain for the switch to matter.