The earth is flat and we never went to the moon

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JudgeRightly

JudgeRightly

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DFT_Dave said:
Flat plane vs curvature experiment

Using this picture to determine flatness vs curvature we can further test for an answer by imagining our self traveling in our car from point A, in the picture, to point B, which is 3 miles ahead to where our vanishing point is. If we see flatness from point B to the next 3 mile vanishing point ahead of us, at point C, and if we can look behind us and see the 3 mile vanishing point we came from, at point A, we have established 6 miles with no curvature. If we go 3 more miles from B to C and can look back and see the flatness behind us as well as 3 more miles of flatness ahead of us to point D we have established 9 miles of flat earth.

View attachment 25207

View attachment 25210

From the Pythagorean curvature chart we can see that the curved earth drops 6 feet from point A to point B in 3 miles. The earth drops 24 feet from point A to point C in 6 miles. The earth drops 54 feet from point A to point D in 9 miles.

Do we traveled 9 miles from point A to point D on a flat plane or do we drop 54 feet in 9 miles on a curved earth without realizing or seeing it?

--Dave
Click to expand...

Don't forget you have to count for atmospheric refraction.

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glassjester

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DFT_Dave said:
or do we drop 54 feet in 9 miles on a curved earth without realizing or seeing it?
Click to expand...

Yes, exactly that. Over the course of 9 miles, you can easily drop 54 feet without noticing it.

Try graphing that as line.
9 miles = 9 x 5280 = 47520 feet.
A horizontal distance of 47520 feet, with a drop of only 54 feet gives us a slope of about .00114.

Here's an equation for that line: Y = .00114X x B

Here's what that line looks like, with the Y-intercept set at 5000, and the range of the graph at 15000 (about 3 miles in each direction).

2lic0gk.jpg


Is the vertical change noticeable?
 
JudgeRightly

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glassjester said:
Yes, exactly that. Over the course of 9 miles, you can easily drop 54 feet without noticing it.

Try graphing that as line.
9 miles = 9 x 5280 = 47520 feet.
A horizontal distance of 47520 feet, with a drop of only 54 feet gives us a slope of about .00114.

Here's an equation for that line: Y = .00114X x B

Here's what that line looks like, with the Y-intercept set at 5000, and the range of the graph at 15000 (about 3 miles in each direction).

2lic0gk.jpg


Is the vertical change noticeable?
Click to expand...
I think Dave's problem is that he forgets that no matter where we are on the Earth, straight down is towards the center of the Earth, and that no matter where we are on the Earth, we will always be standing perpendicular to the tangent of the curve of the Earth.

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glassjester

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JudgeRightly said:
I think Dave's problem is that he forgets that no matter where we are on the Earth, straight down is towards the center of the Earth, and that no matter where we are on the Earth, we will always be standing perpendicular to the tangent of the curve of the Earth.
Click to expand...

The problem could also be a failure to grasp just how minuscule 54 feet is, when compared to 9 miles.
 
ok doser

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DFT_Dave said:
There is no edge that we can reach because there is an Ice Wall surrounding the oceans called Antarctica in the flat earth model. No can go there even to explore! Flights never go "over" Antarctic, they only hit the edges.
Click to expand...

Knight said:
Why couldn't planes at high altitude or satellites gather images of the "edge" of the earth?
Click to expand...

dave, can you answer knight's question?


and can you explain why "No can go there even to explore!"
 
Clete

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DFT_Dave said:
Flat plane vs curvature experiment

Using this picture to determine flatness vs curvature we can further test for an answer by imagining our self traveling in our car from point A, in the picture, to point B, which is 3 miles ahead to where our vanishing point is. If we see flatness from point B to the next 3 mile vanishing point ahead of us, at point C, and if we can look behind us and see the 3 mile vanishing point we came from, at point A, we have established 6 miles with no curvature. If we go 3 more miles from B to C and can look back and see the flatness behind us as well as 3 more miles of flatness ahead of us to point D we have established 9 miles of flat earth.

View attachment 25207

View attachment 25210

From the Pythagorean curvature chart we can see that the curved earth drops 6 feet from point A to point B in 3 miles. The earth drops 24 feet from point A to point C in 6 miles. The earth drops 54 feet from point A to point D in 9 miles.

Do we traveled 9 miles from point A to point D on a flat plane or do we drop 54 feet in 9 miles on a curved earth without realizing or seeing it?

--Dave
Click to expand...
There are at least two things wrong with this thought experiment.

1. Roads are built by people who can introduce more flatness than is there naturally. Therefore roads are not the best things to use for such an experiment. It would be better to use something we know is "level" such as the surface of a lake.

2. The argument you've cited has their number off by a factor of 9!
The curvature of the Earth is nowhere near 54 feet in 9 miles. It's more like 8 inches per mile. So over 9 miles, the curvature would be 72 inches or 6 feet, not 54 feet!

There are 5280 feet per mile so the drop due to the curvature of the earth, at 8 inches (2/3 of a foot) per mile is about 0.00012626%. No road anywhere in the world is that perfectly flat over a 9 mile stretch of road and even if it were perfectly level, where every point along the road was perfectly perpendicular to the center of the Earth, there's no way imaginable that you could detect it with your naked eyes unless you were way-way far away! In fact, the curvature of the Earth is not detectable by the naked eye until you're more than six and a half miles above its surface.
 
glassjester

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DFT_Dave said:
There is no edge that we can reach because there is an Ice Wall surrounding the oceans called Antarctica in the flat earth model. No can go there even to explore! Flights never go "over" Antarctic, they only hit the edges.
Click to expand...

How tall is the ice wall?

Why has no one ever seen the ice wall?

Does the ice wall surround the entire Earth?

What's on the other side of the ice wall?

What countries or oceans border the ice wall?
 
ok doser

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lifeguard at the cement pond
Dave, correct me if i'm wrong, but this is your flat earth model, yes?

FlatEarthCircle.jpg



and this is the round earth model, showing Antarctica:

1452474729.jpg



what measurement does your model give for the perimeter of Antarctica?
 
ok doser

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lifeguard at the cement pond
on a flat earth model, how do you account for the polar ice cap in the north (which in your model is in the center)?
 
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